Write a program find the reverse of any number using java
There we will learn how to find the reverse of any numbers. that number may have N numbers of digits.
For Example.
The actual number which is input by user is: 12678
the reverse number of that number is: 87621
ALGORITHM:-

Step 1: Import java.io.* package
Step 2: Create a class
Step 3: Define main method
Step 4: Input any number from user
Step 5: While(a>0) then Calc the Mod 10 and store in another variable
Step 6: Take another variable and multiple by 10 and add with Calculated mod value
Step 7: Divide the actual number by 10
Step 8: Repeat the 5,6,7 Steps until a>0
Step 9: Display the reverse number
Step 10:Exit




import java.io.*;
class addition
{
     public static void main(String rags[])
     {
         try
         {
             Console con=System.console();
             int a,rev=0,b=0;
             //input in float and int using console class
             System.out.println("Enter Any Numbers to find the reverse of them");
             a=Integer.parseInt(con.readLine());   
             while(a>0)//Checking while a is not zero
             {
                 b=a%10;
                 rev=rev*10+b;
                 a=a/10;
             }
             System.out.println("Reverse number is:  "+rev);
        }
        catch(Exception er)
        {
             System.out.println(er);
        }
    }
}

OUTPUR:-

Enter Any Numbers to find the reverse of them
1285
Reverse number is: 5821




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